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0.5x^2+3x=-2
We move all terms to the left:
0.5x^2+3x-(-2)=0
We add all the numbers together, and all the variables
0.5x^2+3x+2=0
a = 0.5; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·0.5·2
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{5}}{2*0.5}=\frac{-3-\sqrt{5}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{5}}{2*0.5}=\frac{-3+\sqrt{5}}{1} $
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